13121240333 has 2 divisors, whose sum is σ = 13121240334. Its totient is φ = 13121240332.

The previous prime is 13121240317. The next prime is 13121240347. The reversal of 13121240333 is 33304212131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7311447049 + 5809793284 = 85507^2 + 76222^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121240333 - 2⁴ = 13121240317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13121240299 and 13121240308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13121240233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560620166 + 6560620167.

It is an arithmetic number, because the mean of its divisors is an integer number (6560620167).

Almost surely, 2^13121240333 is an apocalyptic number.

It is an amenable number.

13121240333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121240333 is an equidigital number, since it uses as much as digits as its factorization.

13121240333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13121240333 its reverse (33304212131), we get a palindrome (46425452464).

The spelling of 13121240333 in words is "thirteen billion, one hundred twenty-one million, two hundred forty thousand, three hundred thirty-three".