13121303011121 has 2 divisors, whose sum is σ = 13121303011122. Its totient is φ = 13121303011120.

The previous prime is 13121303011087. The next prime is 13121303011123. The reversal of 13121303011121 is 12111030312131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7002056899600 + 6119246111521 = 2646140^2 + 2473711^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121303011121 - 2⁶ = 13121303011057 is a prime.

Together with 13121303011123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13121303011093 and 13121303011102.

It is not a weakly prime, because it can be changed into another prime (13121303011123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560651505560 + 6560651505561.

It is an arithmetic number, because the mean of its divisors is an integer number (6560651505561).

Almost surely, 2^{13121303011121} is an apocalyptic number.

It is an amenable number.

13121303011121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121303011121 is an equidigital number, since it uses as much as digits as its factorization.

13121303011121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 13121303011121 its reverse (12111030312131), we get a palindrome (25232333323252).

The spelling of 13121303011121 in words is "thirteen trillion, one hundred twenty-one billion, three hundred three million, eleven thousand, one hundred twenty-one".