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131213100121440 = 25352928135279511
BaseRepresentation
bin11101110101011001101110…
…001110001111110101100000
3122012120211221112220112000020
4131311121232032033311200
5114144243412112341230
61143022244355353440
736431555640461421
oct3565315616176540
9565524845815006
10131213100121440
1138899188333467
1212871b898b2880
13582a45abc872c
142458a68475648
1510282493b1810
hex77566e38fd60

131213100121440 has 384 divisors, whose sum is σ = 429262126110720. Its totient is φ = 33650293555200.

The previous prime is 131213100121429. The next prime is 131213100121457. The reversal of 131213100121440 is 44121001312131.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 131213100121440.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 13795926285 + ... + 13795935795.

It is an arithmetic number, because the mean of its divisors is an integer number (1117870120080).

Almost surely, 2131213100121440 is an apocalyptic number.

131213100121440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131213100121440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214631063055360).

131213100121440 is an abundant number, since it is smaller than the sum of its proper divisors (298049025989280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131213100121440 is a wasteful number, since it uses less digits than its factorization.

131213100121440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13366 (or 13358 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 131213100121440 its reverse (44121001312131), we get a palindrome (175334101433571).

The spelling of 131213100121440 in words is "one hundred thirty-one trillion, two hundred thirteen billion, one hundred million, one hundred twenty-one thousand, four hundred forty".