Base | Representation |
---|---|
bin | 111101000110011101… |
… | …0010011100000101111 |
3 | 110112200110121210100102 |
4 | 1322030322103200233 |
5 | 4122211024112031 |
6 | 140140052221315 |
7 | 12323404030043 |
oct | 1721472234057 |
9 | 415613553312 |
10 | 131213113391 |
11 | 50713422188 |
12 | 2151b00a83b |
13 | c4b130a9c9 |
14 | 64ca650023 |
15 | 362e5de7cb |
hex | 1e8ce9382f |
131213113391 has 2 divisors, whose sum is σ = 131213113392. Its totient is φ = 131213113390.
The previous prime is 131213113337. The next prime is 131213113411. The reversal of 131213113391 is 193311312131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131213113391 - 226 = 131146004527 is a prime.
It is a super-2 number, since 2×1312131133912 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131213113321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606556695 + 65606556696.
It is an arithmetic number, because the mean of its divisors is an integer number (65606556696).
Almost surely, 2131213113391 is an apocalyptic number.
131213113391 is a deficient number, since it is larger than the sum of its proper divisors (1).
131213113391 is an equidigital number, since it uses as much as digits as its factorization.
131213113391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1458, while the sum is 29.
The spelling of 131213113391 in words is "one hundred thirty-one billion, two hundred thirteen million, one hundred thirteen thousand, three hundred ninety-one".
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