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13121322022321 is a prime number
BaseRepresentation
bin1011111011110000101110…
…1111001111010110110001
31201110101102111021211110121
42332330023233033112301
53204434431414203241
643523504020330241
72522661406645312
oct276741357172661
951411374254417
1013121322022321
1141a97a3233847
12157b000243981
13742448a1b4c6
1433510ab82609
1517b4b072cad1
hexbef0bbcf5b1

13121322022321 has 2 divisors, whose sum is σ = 13121322022322. Its totient is φ = 13121322022320.

The previous prime is 13121322022313. The next prime is 13121322022331. The reversal of 13121322022321 is 12322022312131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11199463833600 + 1921858188721 = 3346560^2 + 1386311^2 .

It is a cyclic number.

It is not a de Polignac number, because 13121322022321 - 23 = 13121322022313 is a prime.

It is a super-2 number, since 2×131213220223212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13121322022301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560661011160 + 6560661011161.

It is an arithmetic number, because the mean of its divisors is an integer number (6560661011161).

Almost surely, 213121322022321 is an apocalyptic number.

It is an amenable number.

13121322022321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13121322022321 is an equidigital number, since it uses as much as digits as its factorization.

13121322022321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13121322022321 its reverse (12322022312131), we get a palindrome (25443344334452).

The spelling of 13121322022321 in words is "thirteen trillion, one hundred twenty-one billion, three hundred twenty-two million, twenty-two thousand, three hundred twenty-one".