Base | Representation |
---|---|
bin | 1011111011110000110001… |
… | …1010000000001001000111 |
3 | 1201110101110021101100112021 |
4 | 2332330030122000021013 |
5 | 3204434442301412244 |
6 | 43523505100504011 |
7 | 2522661604144213 |
oct | 276741432001107 |
9 | 51411407340467 |
10 | 13121333232199 |
11 | 41a97a959aa05 |
12 | 157b003b4b007 |
13 | 74244b14497a |
14 | 33510c45d943 |
15 | 17b4b16e4284 |
hex | bef0c680247 |
13121333232199 has 2 divisors, whose sum is σ = 13121333232200. Its totient is φ = 13121333232198.
The previous prime is 13121333232193. The next prime is 13121333232209. The reversal of 13121333232199 is 99123233312131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121333232199 - 27 = 13121333232071 is a prime.
It is a super-4 number, since 4×131213332321994 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121333232193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560666616099 + 6560666616100.
It is an arithmetic number, because the mean of its divisors is an integer number (6560666616100).
Almost surely, 213121333232199 is an apocalyptic number.
13121333232199 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121333232199 is an equidigital number, since it uses as much as digits as its factorization.
13121333232199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 157464, while the sum is 43.
The spelling of 13121333232199 in words is "thirteen trillion, one hundred twenty-one billion, three hundred thirty-three million, two hundred thirty-two thousand, one hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •