Base | Representation |
---|---|
bin | 10011000110000001101… |
… | …000111101010101001000 |
3 | 11122102212021221112011210 |
4 | 103012001220331111020 |
5 | 132444230321214422 |
6 | 2442442214253120 |
7 | 163541024112642 |
oct | 23060150752510 |
9 | 4572767845153 |
10 | 1312140023112 |
11 | 466525921246 |
12 | 1923750571a0 |
13 | 96971276979 |
14 | 47717a15892 |
15 | 241e9b0410c |
hex | 13181a3d548 |
1312140023112 has 32 divisors (see below), whose sum is σ = 3280751618400. Its totient is φ = 437326466304.
The previous prime is 1312140023111. The next prime is 1312140023113. The reversal of 1312140023112 is 2113200412131.
It is an interprime number because it is at equal distance from previous prime (1312140023111) and next prime (1312140023113).
It is a super-2 number, since 2×13121400231122 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312140023111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3145953 + ... + 3538544.
It is an arithmetic number, because the mean of its divisors is an integer number (102523488075).
Almost surely, 21312140023112 is an apocalyptic number.
1312140023112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1312140023112 is an abundant number, since it is smaller than the sum of its proper divisors (1968611595288).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1312140023112 is a wasteful number, since it uses less digits than its factorization.
1312140023112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6692685 (or 6692681 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 1312140023112 its reverse (2113200412131), we get a palindrome (3425340435243).
The spelling of 1312140023112 in words is "one trillion, three hundred twelve billion, one hundred forty million, twenty-three thousand, one hundred twelve".
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