1312140441330 has 48 divisors (see below), whose sum is σ = 3411626249304. Its totient is φ = 349897850880.

The previous prime is 1312140441329. The next prime is 1312140441343. The reversal of 1312140441330 is 331440412131.

1312140441330 is a `hidden beast` number, since 1 + 3 + 1 + 214 + 0 + 4 + 413 + 30 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 1234585432161 + 77555009169 = 1111119^2 + 278487^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1312140441294 and 1312140441303.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7190620 + ... + 7370840.

Almost surely, 2^{1312140441330} is an apocalyptic number.

1312140441330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1312140441330 is an abundant number, since it is smaller than the sum of its proper divisors (2099485807974).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1312140441330 is a wasteful number, since it uses less digits than its factorization.

1312140441330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261131 (or 261128 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1312140441330 its reverse (331440412131), we get a palindrome (1643580853461).

The spelling of 1312140441330 in words is "one trillion, three hundred twelve billion, one hundred forty million, four hundred forty-one thousand, three hundred thirty".