Base | Representation |
---|---|
bin | 10011000110000001101… |
… | …100110011111111011111 |
3 | 11122102212100211212002022 |
4 | 103012001230303333133 |
5 | 132444231101032224 |
6 | 2442442252050355 |
7 | 163541035521335 |
oct | 23060154637737 |
9 | 4572770755068 |
10 | 1312141033439 |
11 | 466526451325 |
12 | 1923754639bb |
13 | 9697153b7b2 |
14 | 47717bd9b55 |
15 | 241e9c5365e |
hex | 13181b33fdf |
1312141033439 has 2 divisors, whose sum is σ = 1312141033440. Its totient is φ = 1312141033438.
The previous prime is 1312141033403. The next prime is 1312141033471. The reversal of 1312141033439 is 9343301412131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312141033439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312141033399 and 1312141033408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312141033499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656070516719 + 656070516720.
It is an arithmetic number, because the mean of its divisors is an integer number (656070516720).
Almost surely, 21312141033439 is an apocalyptic number.
1312141033439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312141033439 is an equidigital number, since it uses as much as digits as its factorization.
1312141033439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 1312141033439 in words is "one trillion, three hundred twelve billion, one hundred forty-one million, thirty-three thousand, four hundred thirty-nine".
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