Base | Representation |
---|---|
bin | 1011111011110001000100… |
… | …1010101011011011010111 |
3 | 1201110101122211200010022001 |
4 | 2332330101022223123113 |
5 | 3204440123223220041 |
6 | 43523521032420131 |
7 | 2522663564053516 |
oct | 276742112533327 |
9 | 51411584603261 |
10 | 13121413101271 |
11 | 41a983a691802 |
12 | 157b026847647 |
13 | 74246185a587 |
14 | 335118cd067d |
15 | 17b4b871e131 |
hex | bef112ab6d7 |
13121413101271 has 2 divisors, whose sum is σ = 13121413101272. Its totient is φ = 13121413101270.
The previous prime is 13121413101263. The next prime is 13121413101283. The reversal of 13121413101271 is 17210131412131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13121413101271 - 23 = 13121413101263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13121413102271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6560706550635 + 6560706550636.
It is an arithmetic number, because the mean of its divisors is an integer number (6560706550636).
Almost surely, 213121413101271 is an apocalyptic number.
13121413101271 is a deficient number, since it is larger than the sum of its proper divisors (1).
13121413101271 is an equidigital number, since it uses as much as digits as its factorization.
13121413101271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 28.
The spelling of 13121413101271 in words is "thirteen trillion, one hundred twenty-one billion, four hundred thirteen million, one hundred one thousand, two hundred seventy-one".
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