13121434330 has 8 divisors (see below), whose sum is σ = 23618581812. Its totient is φ = 5248573728.

The previous prime is 13121434327. The next prime is 13121434331. The reversal of 13121434330 is 3343412131.

It can be written as a sum of positive squares in 2 ways, for example, as 13102694089 + 18740241 = 114467^2 + 4329^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13121434295 and 13121434304.

It is not an unprimeable number, because it can be changed into a prime (13121434331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656071707 + ... + 656071726.

Almost surely, 2^13121434330 is an apocalyptic number.

13121434330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13121434330 is a deficient number, since it is larger than the sum of its proper divisors (10497147482).

13121434330 is a wasteful number, since it uses less digits than its factorization.

13121434330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1312143440.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13121434330 its reverse (3343412131), we get a palindrome (16464846461).

The spelling of 13121434330 in words is "thirteen billion, one hundred twenty-one million, four hundred thirty-four thousand, three hundred thirty".