Base | Representation |
---|---|
bin | 11101110101011010111110… |
… | …010100110010001100101011 |
3 | 122012120222102012200020201221 |
4 | 131311122332110302030223 |
5 | 114144304140131343311 |
6 | 1143023030003522511 |
7 | 36431634146403601 |
oct | 3565327624621453 |
9 | 565528365606657 |
10 | 131214444012331 |
11 | 38899807989599 |
12 | 128722a3989437 |
13 | 582a613460244 |
14 | 2458b54b3d871 |
15 | 10282c7371671 |
hex | 7756be53232b |
131214444012331 has 2 divisors, whose sum is σ = 131214444012332. Its totient is φ = 131214444012330.
The previous prime is 131214444012277. The next prime is 131214444012367. The reversal of 131214444012331 is 133210444412131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131214444012331 - 27 = 131214444012203 is a prime.
It is a super-3 number, since 3×1312144440123313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (131214444018331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65607222006165 + 65607222006166.
It is an arithmetic number, because the mean of its divisors is an integer number (65607222006166).
Almost surely, 2131214444012331 is an apocalyptic number.
131214444012331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131214444012331 is an equidigital number, since it uses as much as digits as its factorization.
131214444012331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 131214444012331 its reverse (133210444412131), we get a palindrome (264424888424462).
The spelling of 131214444012331 in words is "one hundred thirty-one trillion, two hundred fourteen billion, four hundred forty-four million, twelve thousand, three hundred thirty-one".
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