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131220022013 is a prime number
BaseRepresentation
bin111101000110101010…
…0101010001011111101
3110112200221121210012022
41322031110222023331
54122214311201023
6140140500245525
712323516532563
oct1721524521375
9415627553168
10131220022013
1150717310793
12215213a08a5
13c4b2889452
1464cb52ba33
1536300067c8
hex1e8d52a2fd

131220022013 has 2 divisors, whose sum is σ = 131220022014. Its totient is φ = 131220022012.

The previous prime is 131220021953. The next prime is 131220022019. The reversal of 131220022013 is 310220022131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114262252729 + 16957769284 = 338027^2 + 130222^2 .

It is a cyclic number.

It is not a de Polignac number, because 131220022013 - 212 = 131220017917 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131220021982 and 131220022000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131220022019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65610011006 + 65610011007.

It is an arithmetic number, because the mean of its divisors is an integer number (65610011007).

Almost surely, 2131220022013 is an apocalyptic number.

It is an amenable number.

131220022013 is a deficient number, since it is larger than the sum of its proper divisors (1).

131220022013 is an equidigital number, since it uses as much as digits as its factorization.

131220022013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 131220022013 its reverse (310220022131), we get a palindrome (441440044144).

The spelling of 131220022013 in words is "one hundred thirty-one billion, two hundred twenty million, twenty-two thousand, thirteen".