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1312202203153 is a prime number
BaseRepresentation
bin10011000110000101010…
…110001010000000010001
311122110000121221121011021
4103012011112022000101
5132444342231000103
62442452315115441
7163542410456602
oct23060526120021
94573017847137
101312202203153
11466557a31006
12192391a42b81
1396981107caa
1447721d9dda9
15242002d7bbd
hex1318558a011

1312202203153 has 2 divisors, whose sum is σ = 1312202203154. Its totient is φ = 1312202203152.

The previous prime is 1312202203087. The next prime is 1312202203159. The reversal of 1312202203153 is 3513022022131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1309175332864 + 3026870289 = 1144192^2 + 55017^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312202203153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312202203159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656101101576 + 656101101577.

It is an arithmetic number, because the mean of its divisors is an integer number (656101101577).

Almost surely, 21312202203153 is an apocalyptic number.

It is an amenable number.

1312202203153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312202203153 is an equidigital number, since it uses as much as digits as its factorization.

1312202203153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1312202203153 its reverse (3513022022131), we get a palindrome (4825224225284).

The spelling of 1312202203153 in words is "one trillion, three hundred twelve billion, two hundred two million, two hundred three thousand, one hundred fifty-three".