13122113433 has 32 divisors (see below), whose sum is σ = 21448627200. Its totient is φ = 7021861440.

The previous prime is 13122113423. The next prime is 13122113437. The reversal of 13122113433 is 33431122131.

13122113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13122113433 - 2¹² = 13122109337 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13122113437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 655083 + ... + 674816.

It is an arithmetic number, because the mean of its divisors is an integer number (670269600).

Almost surely, 2^13122113433 is an apocalyptic number.

13122113433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13122113433 is a deficient number, since it is larger than the sum of its proper divisors (8326513767).

13122113433 is a wasteful number, since it uses less digits than its factorization.

13122113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1329949.

The product of its digits is 1296, while the sum is 24.

Adding to 13122113433 its reverse (33431122131), we get a palindrome (46553235564).

The spelling of 13122113433 in words is "thirteen billion, one hundred twenty-two million, one hundred thirteen thousand, four hundred thirty-three".