Base | Representation |
---|---|
bin | 10011000110000110000… |
… | …011010100111000101001 |
3 | 11122110001110020012000121 |
4 | 103012012003110320221 |
5 | 132444403243403301 |
6 | 2442453421003241 |
7 | 163542613224604 |
oct | 23060603247051 |
9 | 4573043205017 |
10 | 1312214044201 |
11 | 4665636893a5 |
12 | 1923959b3521 |
13 | 969836c2828 |
14 | 477237a333b |
15 | 242013763a1 |
hex | 131860d4e29 |
1312214044201 has 2 divisors, whose sum is σ = 1312214044202. Its totient is φ = 1312214044200.
The previous prime is 1312214044187. The next prime is 1312214044247. The reversal of 1312214044201 is 1024404122131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1200558490000 + 111655554201 = 1095700^2 + 334149^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312214044201 - 27 = 1312214044073 is a prime.
It is not a weakly prime, because it can be changed into another prime (1312214044291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656107022100 + 656107022101.
It is an arithmetic number, because the mean of its divisors is an integer number (656107022101).
Almost surely, 21312214044201 is an apocalyptic number.
It is an amenable number.
1312214044201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312214044201 is an equidigital number, since it uses as much as digits as its factorization.
1312214044201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1312214044201 its reverse (1024404122131), we get a palindrome (2336618166332).
The spelling of 1312214044201 in words is "one trillion, three hundred twelve billion, two hundred fourteen million, forty-four thousand, two hundred one".
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