Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …010100001010100000011 |
3 | 11122110001212200002111212 |
4 | 103012012122201110003 |
5 | 132444411322440134 |
6 | 2442454155200335 |
7 | 163543016010311 |
oct | 23060632412403 |
9 | 4573055602455 |
10 | 1312220124419 |
11 | 466567061576 |
12 | 192397a460ab |
13 | 96984a411a9 |
14 | 477245070b1 |
15 | 24201b77bce |
hex | 131866a1503 |
1312220124419 has 2 divisors, whose sum is σ = 1312220124420. Its totient is φ = 1312220124418.
The previous prime is 1312220124329. The next prime is 1312220124431. The reversal of 1312220124419 is 9144210222131.
It is a strong prime.
It is an emirp because it is prime and its reverse (9144210222131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1312220124419 - 216 = 1312220058883 is a prime.
It is a super-2 number, since 2×13122201244192 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312220124119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110062209 + 656110062210.
It is an arithmetic number, because the mean of its divisors is an integer number (656110062210).
Almost surely, 21312220124419 is an apocalyptic number.
1312220124419 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312220124419 is an equidigital number, since it uses as much as digits as its factorization.
1312220124419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 32.
The spelling of 1312220124419 in words is "one trillion, three hundred twelve billion, two hundred twenty million, one hundred twenty-four thousand, four hundred nineteen".
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