131222041443433 has 2 divisors, whose sum is σ = 131222041443434. Its totient is φ = 131222041443432.

The previous prime is 131222041443431. The next prime is 131222041443463. The reversal of 131222041443433 is 334344140222131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130534463828224 + 687577615209 = 11425168^2 + 829203^2 .

It is a cyclic number.

It is not a de Polignac number, because 131222041443433 - 2¹ = 131222041443431 is a prime.

Together with 131222041443431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131222041443392 and 131222041443401.

It is not a weakly prime, because it can be changed into another prime (131222041443431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611020721716 + 65611020721717.

It is an arithmetic number, because the mean of its divisors is an integer number (65611020721717).

Almost surely, 2^{131222041443433} is an apocalyptic number.

It is an amenable number.

131222041443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222041443433 is an equidigital number, since it uses as much as digits as its factorization.

131222041443433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 131222041443433 its reverse (334344140222131), we get a palindrome (465566181665564).

The spelling of 131222041443433 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, forty-one million, four hundred forty-three thousand, four hundred thirty-three".