Base | Representation |
---|---|
bin | 11101110101100010000111… |
… | …100000100111100011000111 |
3 | 122012121201012202200100022002 |
4 | 131311202013200213203013 |
5 | 114144420342230132101 |
6 | 1143030335044455515 |
7 | 36432325214653565 |
oct | 3565420740474307 |
9 | 565551182610262 |
10 | 131222114302151 |
11 | 388a1a9362a894 |
12 | 128738846aa59b |
13 | 582b2665a2482 |
14 | 24592816dca35 |
15 | 10285c593ed6b |
hex | 7758878278c7 |
131222114302151 has 2 divisors, whose sum is σ = 131222114302152. Its totient is φ = 131222114302150.
The previous prime is 131222114302073. The next prime is 131222114302157. The reversal of 131222114302151 is 151203411222131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131222114302151 - 214 = 131222114285767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131222114302157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611057151075 + 65611057151076.
It is an arithmetic number, because the mean of its divisors is an integer number (65611057151076).
Almost surely, 2131222114302151 is an apocalyptic number.
131222114302151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222114302151 is an equidigital number, since it uses as much as digits as its factorization.
131222114302151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 131222114302151 its reverse (151203411222131), we get a palindrome (282425525524282).
The spelling of 131222114302151 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, one hundred fourteen million, three hundred two thousand, one hundred fifty-one".
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