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131222129981 is a prime number
BaseRepresentation
bin111101000110101110…
…0101100110100111101
3110112201002120212210012
41322031130230310331
54122220331124411
6140141013353005
712323543462345
oct1721534546475
9415632525705
10131222129981
1150718520508
1221522038765
13c4b3146a77
1464cb919d25
1536302c118b
hex1e8d72cd3d

131222129981 has 2 divisors, whose sum is σ = 131222129982. Its totient is φ = 131222129980.

The previous prime is 131222129971. The next prime is 131222130001. The reversal of 131222129981 is 189921222131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68256265081 + 62965864900 = 261259^2 + 250930^2 .

It is an emirp because it is prime and its reverse (189921222131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131222129981 - 214 = 131222113597 is a prime.

It is a super-2 number, since 2×1312221299812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131222129921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611064990 + 65611064991.

It is an arithmetic number, because the mean of its divisors is an integer number (65611064991).

Almost surely, 2131222129981 is an apocalyptic number.

It is an amenable number.

131222129981 is a deficient number, since it is larger than the sum of its proper divisors (1).

131222129981 is an equidigital number, since it uses as much as digits as its factorization.

131222129981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 41.

The spelling of 131222129981 in words is "one hundred thirty-one billion, two hundred twenty-two million, one hundred twenty-nine thousand, nine hundred eighty-one".