Base | Representation |
---|---|
bin | 1011111011110100000011… |
… | …0110100000100110010011 |
3 | 1201110110201121001022020021 |
4 | 2332331000312200212103 |
5 | 3204443243024323103 |
6 | 43524132251524311 |
7 | 2523022450110022 |
oct | 276750066404623 |
9 | 51413647038207 |
10 | 13122213120403 |
11 | 41aa110235a42 |
12 | 157b20a759697 |
13 | 74255b51908a |
14 | 3351932628b9 |
15 | 17b513a9bbbd |
hex | bef40da0993 |
13122213120403 has 2 divisors, whose sum is σ = 13122213120404. Its totient is φ = 13122213120402.
The previous prime is 13122213120353. The next prime is 13122213120413. The reversal of 13122213120403 is 30402131222131.
13122213120403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122213120403 is a prime.
It is not a weakly prime, because it can be changed into another prime (13122213120413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561106560201 + 6561106560202.
It is an arithmetic number, because the mean of its divisors is an integer number (6561106560202).
Almost surely, 213122213120403 is an apocalyptic number.
13122213120403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122213120403 is an equidigital number, since it uses as much as digits as its factorization.
13122213120403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13122213120403 its reverse (30402131222131), we get a palindrome (43524344342534).
The spelling of 13122213120403 in words is "thirteen trillion, one hundred twenty-two billion, two hundred thirteen million, one hundred twenty thousand, four hundred three".
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