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1312221320027 is a prime number
BaseRepresentation
bin10011000110000110011…
…111000101001101011011
311122110001221220211120122
4103012012133011031123
5132444412124220102
62442454240543455
7163543032120122
oct23060637051533
94573057824518
101312221320027
114665677a8882
12192398321b8b
139698506c457
1447724738ab9
1524201d120a2
hex131867c535b

1312221320027 has 2 divisors, whose sum is σ = 1312221320028. Its totient is φ = 1312221320026.

The previous prime is 1312221319993. The next prime is 1312221320029. The reversal of 1312221320027 is 7200231222131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1312221320027 - 212 = 1312221315931 is a prime.

Together with 1312221320029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312221319978 and 1312221320005.

It is not a weakly prime, because it can be changed into another prime (1312221320029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110660013 + 656110660014.

It is an arithmetic number, because the mean of its divisors is an integer number (656110660014).

Almost surely, 21312221320027 is an apocalyptic number.

1312221320027 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312221320027 is an equidigital number, since it uses as much as digits as its factorization.

1312221320027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 1312221320027 its reverse (7200231222131), we get a palindrome (8512452542158).

The spelling of 1312221320027 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, three hundred twenty thousand, twenty-seven".