Base | Representation |
---|---|
bin | 10011000110000110011… |
… | …111000101001101011011 |
3 | 11122110001221220211120122 |
4 | 103012012133011031123 |
5 | 132444412124220102 |
6 | 2442454240543455 |
7 | 163543032120122 |
oct | 23060637051533 |
9 | 4573057824518 |
10 | 1312221320027 |
11 | 4665677a8882 |
12 | 192398321b8b |
13 | 9698506c457 |
14 | 47724738ab9 |
15 | 24201d120a2 |
hex | 131867c535b |
1312221320027 has 2 divisors, whose sum is σ = 1312221320028. Its totient is φ = 1312221320026.
The previous prime is 1312221319993. The next prime is 1312221320029. The reversal of 1312221320027 is 7200231222131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312221320027 - 212 = 1312221315931 is a prime.
Together with 1312221320029, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312221319978 and 1312221320005.
It is not a weakly prime, because it can be changed into another prime (1312221320029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656110660013 + 656110660014.
It is an arithmetic number, because the mean of its divisors is an integer number (656110660014).
Almost surely, 21312221320027 is an apocalyptic number.
1312221320027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312221320027 is an equidigital number, since it uses as much as digits as its factorization.
1312221320027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 1312221320027 its reverse (7200231222131), we get a palindrome (8512452542158).
The spelling of 1312221320027 in words is "one trillion, three hundred twelve billion, two hundred twenty-one million, three hundred twenty thousand, twenty-seven".
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