Base | Representation |
---|---|
bin | 111101000110101110… |
… | …1011001100101110011 |
3 | 110112201002221012021221 |
4 | 1322031131121211303 |
5 | 4122220403011311 |
6 | 140141021325511 |
7 | 12323545155034 |
oct | 1721535314563 |
9 | 415632835257 |
10 | 131222313331 |
11 | 5071863623a |
12 | 21522106897 |
13 | c4b31ac365 |
14 | 64cb966a8b |
15 | 363030a671 |
hex | 1e8d759973 |
131222313331 has 2 divisors, whose sum is σ = 131222313332. Its totient is φ = 131222313330.
The previous prime is 131222313323. The next prime is 131222313347. The reversal of 131222313331 is 133313222131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131222313331 - 23 = 131222313323 is a prime.
It is a super-2 number, since 2×1312223133312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131222313296 and 131222313305.
It is not a weakly prime, because it can be changed into another prime (131222311331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611156665 + 65611156666.
It is an arithmetic number, because the mean of its divisors is an integer number (65611156666).
Almost surely, 2131222313331 is an apocalyptic number.
131222313331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222313331 is an equidigital number, since it uses as much as digits as its factorization.
131222313331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1944, while the sum is 25.
Adding to 131222313331 its reverse (133313222131), we get a palindrome (264535535462).
The spelling of 131222313331 in words is "one hundred thirty-one billion, two hundred twenty-two million, three hundred thirteen thousand, three hundred thirty-one".
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