Base | Representation |
---|---|
bin | 11101110101100010010100… |
… | …011111100101001011000011 |
3 | 122012121201202221120100112102 |
4 | 131311202110133211023003 |
5 | 114144421314011242313 |
6 | 1143030412425421015 |
7 | 36432333501340241 |
oct | 3565422437451303 |
9 | 565551687510472 |
10 | 131222332134083 |
11 | 388a2095592183 |
12 | 1287392563a76b |
13 | 582b29c7610c8 |
14 | 24592a2603791 |
15 | 10285d9b1ca58 |
hex | 7758947e52c3 |
131222332134083 has 2 divisors, whose sum is σ = 131222332134084. Its totient is φ = 131222332134082.
The previous prime is 131222332134043. The next prime is 131222332134119. The reversal of 131222332134083 is 380431233222131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131222332134083 - 214 = 131222332117699 is a prime.
It is not a weakly prime, because it can be changed into another prime (131222332134043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611166067041 + 65611166067042.
It is an arithmetic number, because the mean of its divisors is an integer number (65611166067042).
Almost surely, 2131222332134083 is an apocalyptic number.
131222332134083 is a deficient number, since it is larger than the sum of its proper divisors (1).
131222332134083 is an equidigital number, since it uses as much as digits as its factorization.
131222332134083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 38.
The spelling of 131222332134083 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred thirty-two million, one hundred thirty-four thousand, eighty-three".
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