Base | Representation |
---|---|
bin | 10011000110000110100… |
… | …110110000000000010011 |
3 | 11122110002002200222012001 |
4 | 103012012212300000103 |
5 | 132444413133032243 |
6 | 2442454352014431 |
7 | 163543055162053 |
oct | 23060646600023 |
9 | 4573062628161 |
10 | 1312223330323 |
11 | 466568951184 |
12 | 192398b31417 |
13 | 969855c4489 |
14 | 47724add563 |
15 | 242020aca4d |
hex | 131869b0013 |
1312223330323 has 2 divisors, whose sum is σ = 1312223330324. Its totient is φ = 1312223330322.
The previous prime is 1312223330291. The next prime is 1312223330351. The reversal of 1312223330323 is 3230333222131.
It is an a-pointer prime, because the next prime (1312223330351) can be obtained adding 1312223330323 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312223330323 - 25 = 1312223330291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1312223330291 and 1312223330300.
It is not a weakly prime, because it can be changed into another prime (1312223330393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656111665161 + 656111665162.
It is an arithmetic number, because the mean of its divisors is an integer number (656111665162).
Almost surely, 21312223330323 is an apocalyptic number.
1312223330323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312223330323 is an equidigital number, since it uses as much as digits as its factorization.
1312223330323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 1312223330323 its reverse (3230333222131), we get a palindrome (4542556552454).
The spelling of 1312223330323 in words is "one trillion, three hundred twelve billion, two hundred twenty-three million, three hundred thirty thousand, three hundred twenty-three".
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