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131223021019 is a prime number
BaseRepresentation
bin111101000110110000…
…0000110010111011011
3110112201011021011001121
41322031200012113123
54122221043133034
6140141044430111
712323554163206
oct1721540062733
9415634234047
10131223021019
1150718a79a02
12215223a8337
13c4b33994cc
1464cbaac93d
1536303ea1b4
hex1e8d8065db

131223021019 has 2 divisors, whose sum is σ = 131223021020. Its totient is φ = 131223021018.

The previous prime is 131223020963. The next prime is 131223021071. The reversal of 131223021019 is 910120322131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131223021019 - 217 = 131222889947 is a prime.

It is a super-2 number, since 2×1312230210192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131223020984 and 131223021002.

It is not a weakly prime, because it can be changed into another prime (131223021079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611510509 + 65611510510.

It is an arithmetic number, because the mean of its divisors is an integer number (65611510510).

Almost surely, 2131223021019 is an apocalyptic number.

131223021019 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223021019 is an equidigital number, since it uses as much as digits as its factorization.

131223021019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 131223021019 in words is "one hundred thirty-one billion, two hundred twenty-three million, twenty-one thousand, nineteen".