Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …111111110101010100011 |
3 | 11122110002201002112011021 |
4 | 103012013013332222203 |
5 | 132444422400303443 |
6 | 2442455302430311 |
7 | 163543222212013 |
oct | 23060707765243 |
9 | 4573081075137 |
10 | 1312232041123 |
11 | 466572860793 |
12 | 19239ba32397 |
13 | 969873542b3 |
14 | 47725d29c43 |
15 | 24202c2d9ed |
hex | 131871feaa3 |
1312232041123 has 2 divisors, whose sum is σ = 1312232041124. Its totient is φ = 1312232041122.
The previous prime is 1312232041103. The next prime is 1312232041129. The reversal of 1312232041123 is 3211402322131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312232041123 - 213 = 1312232032931 is a prime.
It is a super-2 number, since 2×13122320411232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1312232041129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656116020561 + 656116020562.
It is an arithmetic number, because the mean of its divisors is an integer number (656116020562).
Almost surely, 21312232041123 is an apocalyptic number.
1312232041123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312232041123 is an equidigital number, since it uses as much as digits as its factorization.
1312232041123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1312232041123 its reverse (3211402322131), we get a palindrome (4523634363254).
The spelling of 1312232041123 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, forty-one thousand, one hundred twenty-three".
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