Search a number
-
+
131223214012573 is a prime number
BaseRepresentation
bin11101110101100011001001…
…000011101011100010011101
3122012121211001101222102101201
4131311203021003223202131
5114144430120241400243
61143031040131235501
736432364400232454
oct3565431103534235
9565554041872351
10131223214012573
11388a24a8367581
1212873b30a48b91
13582b3b03813b7
1424593477a3b9b
15102863c26a04d
hex7758c90eb89d

131223214012573 has 2 divisors, whose sum is σ = 131223214012574. Its totient is φ = 131223214012572.

The previous prime is 131223214012547. The next prime is 131223214012591. The reversal of 131223214012573 is 375210412322131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70374196878489 + 60849017134084 = 8388933^2 + 7800578^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131223214012573 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131223214010573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611607006286 + 65611607006287.

It is an arithmetic number, because the mean of its divisors is an integer number (65611607006287).

Almost surely, 2131223214012573 is an apocalyptic number.

It is an amenable number.

131223214012573 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223214012573 is an equidigital number, since it uses as much as digits as its factorization.

131223214012573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 37.

The spelling of 131223214012573 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, two hundred fourteen million, twelve thousand, five hundred seventy-three".