Base | Representation |
---|---|
bin | 111101000110110000… |
… | …0110110111100010101 |
3 | 110112201011122020222212 |
4 | 1322031200312330111 |
5 | 4122221121014424 |
6 | 140141053003205 |
7 | 12323555652251 |
oct | 1721540667425 |
9 | 415634566885 |
10 | 131223219989 |
11 | 507190a5444 |
12 | 21522483505 |
13 | c4b3438c44 |
14 | 64cbb21261 |
15 | 363043910e |
hex | 1e8d836f15 |
131223219989 has 2 divisors, whose sum is σ = 131223219990. Its totient is φ = 131223219988.
The previous prime is 131223219979. The next prime is 131223220123. The reversal of 131223219989 is 989912322131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77929188964 + 53294031025 = 279158^2 + 230855^2 .
It is an emirp because it is prime and its reverse (989912322131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131223219989 - 228 = 130954784533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131223219949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611609994 + 65611609995.
It is an arithmetic number, because the mean of its divisors is an integer number (65611609995).
Almost surely, 2131223219989 is an apocalyptic number.
It is an amenable number.
131223219989 is a deficient number, since it is larger than the sum of its proper divisors (1).
131223219989 is an equidigital number, since it uses as much as digits as its factorization.
131223219989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 419904, while the sum is 50.
The spelling of 131223219989 in words is "one hundred thirty-one billion, two hundred twenty-three million, two hundred nineteen thousand, nine hundred eighty-nine".
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