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131223219989 is a prime number
BaseRepresentation
bin111101000110110000…
…0110110111100010101
3110112201011122020222212
41322031200312330111
54122221121014424
6140141053003205
712323555652251
oct1721540667425
9415634566885
10131223219989
11507190a5444
1221522483505
13c4b3438c44
1464cbb21261
15363043910e
hex1e8d836f15

131223219989 has 2 divisors, whose sum is σ = 131223219990. Its totient is φ = 131223219988.

The previous prime is 131223219979. The next prime is 131223220123. The reversal of 131223219989 is 989912322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77929188964 + 53294031025 = 279158^2 + 230855^2 .

It is an emirp because it is prime and its reverse (989912322131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131223219989 - 228 = 130954784533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131223219949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611609994 + 65611609995.

It is an arithmetic number, because the mean of its divisors is an integer number (65611609995).

Almost surely, 2131223219989 is an apocalyptic number.

It is an amenable number.

131223219989 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223219989 is an equidigital number, since it uses as much as digits as its factorization.

131223219989 is an evil number, because the sum of its binary digits is even.

The product of its digits is 419904, while the sum is 50.

The spelling of 131223219989 in words is "one hundred thirty-one billion, two hundred twenty-three million, two hundred nineteen thousand, nine hundred eighty-nine".