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131223232031093 is a prime number
BaseRepresentation
bin11101110101100011001010…
…001000011010100101110101
3122012121211002122212212011022
4131311203022020122211311
5114144430134344443333
61143031042013350525
736432365006336546
oct3565431210324565
9565554078785138
10131223232031093
11388a2507554114
1212873b36a98445
13582b3b401c947
142459349d344cd
15102863db28c98
hex7758ca21a975

131223232031093 has 2 divisors, whose sum is σ = 131223232031094. Its totient is φ = 131223232031092.

The previous prime is 131223232031071. The next prime is 131223232031149. The reversal of 131223232031093 is 390130232322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 125102838063844 + 6120393967249 = 11184938^2 + 2473943^2 .

It is a cyclic number.

It is not a de Polignac number, because 131223232031093 - 216 = 131223231965557 is a prime.

It is a super-2 number, since 2×1312232320310932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131223232031033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65611616015546 + 65611616015547.

It is an arithmetic number, because the mean of its divisors is an integer number (65611616015547).

Almost surely, 2131223232031093 is an apocalyptic number.

It is an amenable number.

131223232031093 is a deficient number, since it is larger than the sum of its proper divisors (1).

131223232031093 is an equidigital number, since it uses as much as digits as its factorization.

131223232031093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 35.

The spelling of 131223232031093 in words is "one hundred thirty-one trillion, two hundred twenty-three billion, two hundred thirty-two million, thirty-one thousand, ninety-three".