Base | Representation |
---|---|
bin | 1011111011110100011101… |
… | …1010100011100110000001 |
3 | 1201110111000021020121112021 |
4 | 2332331013122203212001 |
5 | 3204444004221430103 |
6 | 43524151224001441 |
7 | 2523025255051321 |
oct | 276750732434601 |
9 | 51414007217467 |
10 | 13122323233153 |
11 | 41aa167404312 |
12 | 157b23b600281 |
13 | 742578290854 |
14 | 3351a3b27281 |
15 | 17b51d59cbbd |
hex | bef476a3981 |
13122323233153 has 2 divisors, whose sum is σ = 13122323233154. Its totient is φ = 13122323233152.
The previous prime is 13122323233127. The next prime is 13122323233213. The reversal of 13122323233153 is 35133232322131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13062781377009 + 59541856144 = 3614247^2 + 244012^2 .
It is a cyclic number.
It is not a de Polignac number, because 13122323233153 - 237 = 12984884279681 is a prime.
It is not a weakly prime, because it can be changed into another prime (13122323231153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561161616576 + 6561161616577.
It is an arithmetic number, because the mean of its divisors is an integer number (6561161616577).
Almost surely, 213122323233153 is an apocalyptic number.
It is an amenable number.
13122323233153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122323233153 is an equidigital number, since it uses as much as digits as its factorization.
13122323233153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 58320, while the sum is 34.
Adding to 13122323233153 its reverse (35133232322131), we get a palindrome (48255555555284).
The spelling of 13122323233153 in words is "thirteen trillion, one hundred twenty-two billion, three hundred twenty-three million, two hundred thirty-three thousand, one hundred fifty-three".
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