Base | Representation |
---|---|
bin | 10011000110000111001… |
… | …011011111101101100111 |
3 | 11122110002202211100121212 |
4 | 103012013023133231213 |
5 | 132444423114303134 |
6 | 2442455334302035 |
7 | 163543233101324 |
oct | 23060713375547 |
9 | 4573082740555 |
10 | 1312232962919 |
11 | 4665733302aa |
12 | 1923a01b791b |
13 | 969875b7a38 |
14 | 477260c9b4b |
15 | 24202d61bce |
hex | 131872dfb67 |
1312232962919 has 2 divisors, whose sum is σ = 1312232962920. Its totient is φ = 1312232962918.
The previous prime is 1312232962903. The next prime is 1312232962933. The reversal of 1312232962919 is 9192692322131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312232962919 - 24 = 1312232962903 is a prime.
It is a super-2 number, since 2×13122329629192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312232992919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656116481459 + 656116481460.
It is an arithmetic number, because the mean of its divisors is an integer number (656116481460).
Almost surely, 21312232962919 is an apocalyptic number.
1312232962919 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312232962919 is an equidigital number, since it uses as much as digits as its factorization.
1312232962919 is an evil number, because the sum of its binary digits is even.
The product of its digits is 629856, while the sum is 50.
The spelling of 1312232962919 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, nine hundred sixty-two thousand, nine hundred nineteen".
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