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13122350433253 is a prime number
BaseRepresentation
bin1011111011110100100100…
…0010010100001111100101
31201110111002011102112001101
42332331021002110033211
53204444033202331003
643524154035000101
72523026035206025
oct276751102241745
951414064375041
1013122350433253
1141aa1807a2136
12157b248739031
13742580ac5299
143351a75a7a85
1517b520b7211d
hexbef490943e5

13122350433253 has 2 divisors, whose sum is σ = 13122350433254. Its totient is φ = 13122350433252.

The previous prime is 13122350433233. The next prime is 13122350433329. The reversal of 13122350433253 is 35233405322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8933152590244 + 4189197843009 = 2988838^2 + 2046753^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122350433253 - 233 = 13113760498661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122350433233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561175216626 + 6561175216627.

It is an arithmetic number, because the mean of its divisors is an integer number (6561175216627).

Almost surely, 213122350433253 is an apocalyptic number.

It is an amenable number.

13122350433253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122350433253 is an equidigital number, since it uses as much as digits as its factorization.

13122350433253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 13122350433253 its reverse (35233405322131), we get a palindrome (48355755755384).

The spelling of 13122350433253 in words is "thirteen trillion, one hundred twenty-two billion, three hundred fifty million, four hundred thirty-three thousand, two hundred fifty-three".