13122350545441 has 2 divisors, whose sum is σ = 13122350545442. Its totient is φ = 13122350545440.

The previous prime is 13122350545439. The next prime is 13122350545477. The reversal of 13122350545441 is 14454505322131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12622778651025 + 499571894416 = 3552855^2 + 706804^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122350545441 - 2¹ = 13122350545439 is a prime.

Together with 13122350545439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13122350545394 and 13122350545403.

It is not a weakly prime, because it can be changed into another prime (13122350545141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561175272720 + 6561175272721.

It is an arithmetic number, because the mean of its divisors is an integer number (6561175272721).

Almost surely, 2^{13122350545441} is an apocalyptic number.

It is an amenable number.

13122350545441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122350545441 is an equidigital number, since it uses as much as digits as its factorization.

13122350545441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 13122350545441 its reverse (14454505322131), we get a palindrome (27576855867572).

The spelling of 13122350545441 in words is "thirteen trillion, one hundred twenty-two billion, three hundred fifty million, five hundred forty-five thousand, four hundred forty-one".