Base | Representation |
---|---|
bin | 10011000110000111100… |
… | …111111000001011000101 |
3 | 11122110010021211100200122 |
4 | 103012013213320023011 |
5 | 132444432020400031 |
6 | 2442500201551325 |
7 | 163543353250043 |
oct | 23060747701305 |
9 | 4573107740618 |
10 | 1312240403141 |
11 | 466577552248 |
12 | 1923a27a5545 |
13 | 96988cc1435 |
14 | 477270a5393 |
15 | 2420383147b |
hex | 131879f82c5 |
1312240403141 has 2 divisors, whose sum is σ = 1312240403142. Its totient is φ = 1312240403140.
The previous prime is 1312240403101. The next prime is 1312240403147. The reversal of 1312240403141 is 1413040422131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1299495122116 + 12745281025 = 1139954^2 + 112895^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1312240403141 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312240403141.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312240403147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656120201570 + 656120201571.
It is an arithmetic number, because the mean of its divisors is an integer number (656120201571).
Almost surely, 21312240403141 is an apocalyptic number.
It is an amenable number.
1312240403141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312240403141 is an equidigital number, since it uses as much as digits as its factorization.
1312240403141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1312240403141 its reverse (1413040422131), we get a palindrome (2725280825272).
The spelling of 1312240403141 in words is "one trillion, three hundred twelve billion, two hundred forty million, four hundred three thousand, one hundred forty-one".
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