Search a number
-
+
1312240403143 = 3277140042733
BaseRepresentation
bin10011000110000111100…
…111111000001011000111
311122110010021211100200201
4103012013213320023013
5132444432020400033
62442500201551331
7163543353250045
oct23060747701307
94573107740621
101312240403143
1146657755224a
121923a27a5547
1396988cc1437
14477270a5395
152420383147d
hex131879f82c7

1312240403143 has 4 divisors (see below), whose sum is σ = 1312280478648. Its totient is φ = 1312200327640.

The previous prime is 1312240403141. The next prime is 1312240403147. The reversal of 1312240403143 is 3413040422131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312240403143 - 21 = 1312240403141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1312240403141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19988596 + ... + 20054137.

It is an arithmetic number, because the mean of its divisors is an integer number (328070119662).

Almost surely, 21312240403143 is an apocalyptic number.

1312240403143 is a deficient number, since it is larger than the sum of its proper divisors (40075505).

1312240403143 is an equidigital number, since it uses as much as digits as its factorization.

1312240403143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40075504.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1312240403143 its reverse (3413040422131), we get a palindrome (4725280825274).

The spelling of 1312240403143 in words is "one trillion, three hundred twelve billion, two hundred forty million, four hundred three thousand, one hundred forty-three".

Divisors: 1 32771 40042733 1312240403143