Base | Representation |
---|---|
bin | 10011000110000111100… |
… | …111111000001011001001 |
3 | 11122110010021211100200210 |
4 | 103012013213320023021 |
5 | 132444432020400040 |
6 | 2442500201551333 |
7 | 163543353250050 |
oct | 23060747701311 |
9 | 4573107740623 |
10 | 1312240403145 |
11 | 466577552251 |
12 | 1923a27a5549 |
13 | 96988cc1439 |
14 | 477270a5397 |
15 | 24203831480 |
hex | 131879f82c9 |
1312240403145 has 32 divisors (see below), whose sum is σ = 2400715346688. Its totient is φ = 599583817728.
The previous prime is 1312240403141. The next prime is 1312240403147. The reversal of 1312240403145 is 5413040422131.
It is not a de Polignac number, because 1312240403145 - 22 = 1312240403141 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1312240403141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2886264 + ... + 3309833.
It is an arithmetic number, because the mean of its divisors is an integer number (75022354584).
Almost surely, 21312240403145 is an apocalyptic number.
1312240403145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1312240403145 is a deficient number, since it is larger than the sum of its proper divisors (1088474943543).
1312240403145 is a wasteful number, since it uses less digits than its factorization.
1312240403145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6198129.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1312240403145 its reverse (5413040422131), we get a palindrome (6725280825276).
The spelling of 1312240403145 in words is "one trillion, three hundred twelve billion, two hundred forty million, four hundred three thousand, one hundred forty-five".
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