Base | Representation |
---|---|
bin | 111101000110110001… |
… | …1111111111000011010 |
3 | 110112201020012002000000 |
4 | 1322031203333320122 |
5 | 4122221323334114 |
6 | 140141122353430 |
7 | 12323565650640 |
oct | 1721543777032 |
9 | 415636162000 |
10 | 131224043034 |
11 | 50719607847 |
12 | 215227bb876 |
13 | c4b3666756 |
14 | 64cbc97190 |
15 | 363054ce09 |
hex | 1e8d8ffe1a |
131224043034 has 112 divisors (see below), whose sum is σ = 338478211392. Its totient is φ = 37359278784.
The previous prime is 131224043023. The next prime is 131224043177. The reversal of 131224043034 is 430340422131.
131224043034 is a `hidden beast` number, since 1 + 3 + 1 + 224 + 0 + 430 + 3 + 4 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 131224042989 and 131224043007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 2865582 + ... + 2911014.
Almost surely, 2131224043034 is an apocalyptic number.
131224043034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 131224043034, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (169239105696).
131224043034 is an abundant number, since it is smaller than the sum of its proper divisors (207254168358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131224043034 is an equidigital number, since it uses as much as digits as its factorization.
131224043034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45743 (or 45728 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 131224043034 its reverse (430340422131), we get a palindrome (561564465165).
The spelling of 131224043034 in words is "one hundred thirty-one billion, two hundred twenty-four million, forty-three thousand, thirty-four".
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