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131224104433421 is a prime number
BaseRepresentation
bin11101110101100011111110…
…001000010111011100001101
3122012121220100110110111011122
4131311203332020113130031
5114144433431213332141
61143031304340130325
736432425431543556
oct3565437610273415
9565556313414148
10131224104433421
11388a2914a4697a
121287413b0969a5
13582b4c29a293c
1424593cdb4932d
15102869050364b
hex7758fe21770d

131224104433421 has 2 divisors, whose sum is σ = 131224104433422. Its totient is φ = 131224104433420.

The previous prime is 131224104433417. The next prime is 131224104433427. The reversal of 131224104433421 is 124334401422131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95183653076521 + 36040451356900 = 9756211^2 + 6003370^2 .

It is a cyclic number.

It is not a de Polignac number, because 131224104433421 - 22 = 131224104433417 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131224104433427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65612052216710 + 65612052216711.

It is an arithmetic number, because the mean of its divisors is an integer number (65612052216711).

Almost surely, 2131224104433421 is an apocalyptic number.

It is an amenable number.

131224104433421 is a deficient number, since it is larger than the sum of its proper divisors (1).

131224104433421 is an equidigital number, since it uses as much as digits as its factorization.

131224104433421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 131224104433421 its reverse (124334401422131), we get a palindrome (255558505855552).

The spelling of 131224104433421 in words is "one hundred thirty-one trillion, two hundred twenty-four billion, one hundred four million, four hundred thirty-three thousand, four hundred twenty-one".