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13122411011231 is a prime number
BaseRepresentation
bin1011111011110100110010…
…1001011001110010011111
31201110111020101102012102012
42332331030221121302133
53204444144204324411
643524204041221435
72523030402131144
oct276751451316237
951414211365365
1013122411011231
1141aa201a08285
12157b264a9187b
13742590515342
143351b16563cb
1517b52613b18b
hexbef4ca59c9f

13122411011231 has 2 divisors, whose sum is σ = 13122411011232. Its totient is φ = 13122411011230.

The previous prime is 13122411011161. The next prime is 13122411011243. The reversal of 13122411011231 is 13211011422131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13122411011231 - 242 = 8724364500127 is a prime.

It is a super-2 number, since 2×131224110112312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13122411011197 and 13122411011206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122411011251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561205505615 + 6561205505616.

It is an arithmetic number, because the mean of its divisors is an integer number (6561205505616).

Almost surely, 213122411011231 is an apocalyptic number.

13122411011231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122411011231 is an equidigital number, since it uses as much as digits as its factorization.

13122411011231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 13122411011231 its reverse (13211011422131), we get a palindrome (26333422433362).

The spelling of 13122411011231 in words is "thirteen trillion, one hundred twenty-two billion, four hundred eleven million, eleven thousand, two hundred thirty-one".