Base | Representation |
---|---|
bin | 1011111011110100110010… |
… | …1001011001110010011111 |
3 | 1201110111020101102012102012 |
4 | 2332331030221121302133 |
5 | 3204444144204324411 |
6 | 43524204041221435 |
7 | 2523030402131144 |
oct | 276751451316237 |
9 | 51414211365365 |
10 | 13122411011231 |
11 | 41aa201a08285 |
12 | 157b264a9187b |
13 | 742590515342 |
14 | 3351b16563cb |
15 | 17b52613b18b |
hex | bef4ca59c9f |
13122411011231 has 2 divisors, whose sum is σ = 13122411011232. Its totient is φ = 13122411011230.
The previous prime is 13122411011161. The next prime is 13122411011243. The reversal of 13122411011231 is 13211011422131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13122411011231 - 242 = 8724364500127 is a prime.
It is a super-2 number, since 2×131224110112312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13122411011197 and 13122411011206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122411011251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561205505615 + 6561205505616.
It is an arithmetic number, because the mean of its divisors is an integer number (6561205505616).
Almost surely, 213122411011231 is an apocalyptic number.
13122411011231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122411011231 is an equidigital number, since it uses as much as digits as its factorization.
13122411011231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 13122411011231 its reverse (13211011422131), we get a palindrome (26333422433362).
The spelling of 13122411011231 in words is "thirteen trillion, one hundred twenty-two billion, four hundred eleven million, eleven thousand, two hundred thirty-one".
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