Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010111101001001001100 |
3 | 1201110111020120010102101222 |
4 | 2332331030302331021030 |
5 | 3204444200324442330 |
6 | 43524204211022512 |
7 | 2523030432330563 |
oct | 276751462751114 |
9 | 51414216112358 |
10 | 13122413515340 |
11 | 41aa203368698 |
12 | 157b26589aa38 |
13 | 742590bb106c |
14 | 3351b1b08bda |
15 | 17b5264830e5 |
hex | bef4ccbd24c |
13122413515340 has 12 divisors (see below), whose sum is σ = 27557068382256. Its totient is φ = 5248965406128.
The previous prime is 13122413515339. The next prime is 13122413515439. The reversal of 13122413515340 is 4351531422131.
It is a self number, because there is not a number n which added to its sum of digits gives 13122413515340.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328060337864 + ... + 328060337903.
It is an arithmetic number, because the mean of its divisors is an integer number (2296422365188).
Almost surely, 213122413515340 is an apocalyptic number.
13122413515340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13122413515340 is an abundant number, since it is smaller than the sum of its proper divisors (14434654866916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13122413515340 is a wasteful number, since it uses less digits than its factorization.
13122413515340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656120675776 (or 656120675774 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13122413515340 its reverse (4351531422131), we get a palindrome (17473944937471).
The spelling of 13122413515340 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifteen thousand, three hundred forty".
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