Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010111101001010101111 |
3 | 1201110111020120010102112122 |
4 | 2332331030302331022233 |
5 | 3204444200324443224 |
6 | 43524204211023155 |
7 | 2523030432331064 |
oct | 276751462751257 |
9 | 51414216112478 |
10 | 13122413515439 |
11 | 41aa203368778 |
12 | 157b26589aabb |
13 | 742590bb1117 |
14 | 3351b1b08c6b |
15 | 17b52648315e |
hex | bef4ccbd2af |
13122413515439 has 2 divisors, whose sum is σ = 13122413515440. Its totient is φ = 13122413515438.
The previous prime is 13122413515339. The next prime is 13122413515451. The reversal of 13122413515439 is 93451531422131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13122413515439 is a prime.
It is a super-2 number, since 2×131224135154392 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13122413515439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13122413515339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206757719 + 6561206757720.
It is an arithmetic number, because the mean of its divisors is an integer number (6561206757720).
Almost surely, 213122413515439 is an apocalyptic number.
13122413515439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13122413515439 is an equidigital number, since it uses as much as digits as its factorization.
13122413515439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 388800, while the sum is 44.
The spelling of 13122413515439 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, five hundred fifteen thousand, four hundred thirty-nine".
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