Base | Representation |
---|---|
bin | 10011000110000111101… |
… | …011011111101101110001 |
3 | 11122110010100121112122102 |
4 | 103012013223133231301 |
5 | 132444432241222122 |
6 | 2442500234150145 |
7 | 163543364310044 |
oct | 23060753375561 |
9 | 4573110545572 |
10 | 1312241351537 |
11 | 46657803a846 |
12 | 1923a2b82355 |
13 | 9698926400c |
14 | 47727270c5b |
15 | 2420396c492 |
hex | 13187adfb71 |
1312241351537 has 2 divisors, whose sum is σ = 1312241351538. Its totient is φ = 1312241351536.
The previous prime is 1312241351527. The next prime is 1312241351599. The reversal of 1312241351537 is 7351531422131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1039633101376 + 272608250161 = 1019624^2 + 522119^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312241351537 - 216 = 1312241286001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1312241351537.
It is not a weakly prime, because it can be changed into another prime (1312241351507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656120675768 + 656120675769.
It is an arithmetic number, because the mean of its divisors is an integer number (656120675769).
Almost surely, 21312241351537 is an apocalyptic number.
It is an amenable number.
1312241351537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312241351537 is an equidigital number, since it uses as much as digits as its factorization.
1312241351537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 75600, while the sum is 38.
Adding to 1312241351537 its reverse (7351531422131), we get a palindrome (8663772773668).
The spelling of 1312241351537 in words is "one trillion, three hundred twelve billion, two hundred forty-one million, three hundred fifty-one thousand, five hundred thirty-seven".
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