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13122414001313 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0100110011110010100001
31201110111020121001010000222
42332331030310303302201
53204444200441020223
643524204225252425
72523030436423451
oct276751464636241
951414217033028
1013122414001313
1141aa20366a821
12157b265a94115
13742591021316
143351b1bd3d61
1517b52652c0c8
hexbef4cd33ca1

13122414001313 has 2 divisors, whose sum is σ = 13122414001314. Its totient is φ = 13122414001312.

The previous prime is 13122414001297. The next prime is 13122414001369. The reversal of 13122414001313 is 31310041422131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12681055736209 + 441358265104 = 3561047^2 + 664348^2 .

It is an emirp because it is prime and its reverse (31310041422131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122414001313 - 24 = 13122414001297 is a prime.

It is not a weakly prime, because it can be changed into another prime (13122417001313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000656 + 6561207000657.

It is an arithmetic number, because the mean of its divisors is an integer number (6561207000657).

Almost surely, 213122414001313 is an apocalyptic number.

It is an amenable number.

13122414001313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122414001313 is an equidigital number, since it uses as much as digits as its factorization.

13122414001313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13122414001313 its reverse (31310041422131), we get a palindrome (44432455423444).

The spelling of 13122414001313 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, one thousand, three hundred thirteen".