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13122414001369 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0100110011110011011001
31201110111020121001010010001
42332331030310303303121
53204444200441020434
643524204225253001
72523030436423561
oct276751464636331
951414217033101
1013122414001369
1141aa20366a872
12157b265a94161
1374259102135a
143351b1bd3da1
1517b52652c114
hexbef4cd33cd9

13122414001369 has 2 divisors, whose sum is σ = 13122414001370. Its totient is φ = 13122414001368.

The previous prime is 13122414001313. The next prime is 13122414001379. The reversal of 13122414001369 is 96310041422131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10921306467600 + 2201107533769 = 3304740^2 + 1483613^2 .

It is a cyclic number.

It is not a de Polignac number, because 13122414001369 - 217 = 13122413870297 is a prime.

It is a super-2 number, since 2×131224140013692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13122414001379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561207000684 + 6561207000685.

It is an arithmetic number, because the mean of its divisors is an integer number (6561207000685).

Almost surely, 213122414001369 is an apocalyptic number.

It is an amenable number.

13122414001369 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122414001369 is an equidigital number, since it uses as much as digits as its factorization.

13122414001369 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 13122414001369 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fourteen million, one thousand, three hundred sixty-nine".