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13122454011013 is a prime number
BaseRepresentation
bin1011111011110100111100…
…1101011011110010000101
31201110111100101022211000201
42332331033031123302011
53204444241211323023
643524212215010501
72523031433462014
oct276751715336205
951414311284021
1013122454011013
1141aa224207696
12157b277369a31
137425993bc3b9
143351b724aa7b
1517b529cd1bad
hexbef4f35bc85

13122454011013 has 2 divisors, whose sum is σ = 13122454011014. Its totient is φ = 13122454011012.

The previous prime is 13122454011001. The next prime is 13122454011047. The reversal of 13122454011013 is 31011045422131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11690607237409 + 1431846773604 = 3419153^2 + 1196598^2 .

It is an emirp because it is prime and its reverse (31011045422131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13122454011013 - 213 = 13122454002821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122454011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561227005506 + 6561227005507.

It is an arithmetic number, because the mean of its divisors is an integer number (6561227005507).

Almost surely, 213122454011013 is an apocalyptic number.

It is an amenable number.

13122454011013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122454011013 is an equidigital number, since it uses as much as digits as its factorization.

13122454011013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13122454011013 its reverse (31011045422131), we get a palindrome (44133499433144).

The spelling of 13122454011013 in words is "thirteen trillion, one hundred twenty-two billion, four hundred fifty-four million, eleven thousand, thirteen".