Base | Representation |
---|---|
bin | 10011000110001000001… |
… | …100101011101000110010 |
3 | 11122110010221222112020021 |
4 | 103012020030223220302 |
5 | 132444442003113442 |
6 | 2442501144434054 |
7 | 163543531252213 |
oct | 23061014535062 |
9 | 4573127875207 |
10 | 1312250051122 |
11 | 466581a4198a |
12 | 1923a5a7892a |
13 | 9698acbb9ba |
14 | 4772849740a |
15 | 242045d9e67 |
hex | 1318832ba32 |
1312250051122 has 4 divisors (see below), whose sum is σ = 1968375076686. Its totient is φ = 656125025560.
The previous prime is 1312250051113. The next prime is 1312250051129. The reversal of 1312250051122 is 2211500522131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 883710923481 + 428539127641 = 940059^2 + 654629^2 .
It is a super-2 number, since 2×13122500511222 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1312250051129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328062512779 + ... + 328062512782.
Almost surely, 21312250051122 is an apocalyptic number.
1312250051122 is a deficient number, since it is larger than the sum of its proper divisors (656125025564).
1312250051122 is an equidigital number, since it uses as much as digits as its factorization.
1312250051122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656125025563.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 1312250051122 its reverse (2211500522131), we get a palindrome (3523750573253).
The spelling of 1312250051122 in words is "one trillion, three hundred twelve billion, two hundred fifty million, fifty-one thousand, one hundred twenty-two".
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