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13123000139 is a prime number
BaseRepresentation
bin11000011100011000…
…10001011101001011
31020212120020110221012
430032030101131023
5203333442001024
610010103234135
7643125442424
oct141614213513
936776213835
1013123000139
115624656267
122662a4894b
131311a09352
148c6c2664b
1551c14b50e
hex30e31174b

13123000139 has 2 divisors, whose sum is σ = 13123000140. Its totient is φ = 13123000138.

The previous prime is 13123000097. The next prime is 13123000141. The reversal of 13123000139 is 93100032131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13123000139 - 216 = 13122934603 is a prime.

It is a Sophie Germain prime.

Together with 13123000141, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13123000039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561500069 + 6561500070.

It is an arithmetic number, because the mean of its divisors is an integer number (6561500070).

Almost surely, 213123000139 is an apocalyptic number.

13123000139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123000139 is an equidigital number, since it uses as much as digits as its factorization.

13123000139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

The spelling of 13123000139 in words is "thirteen billion, one hundred twenty-three million, one hundred thirty-nine", and thus it is an aban number.