Base | Representation |
---|---|
bin | 1011111011110111000001… |
… | …1010100100001000010011 |
3 | 1201110112210012120221002201 |
4 | 2332331300122210020103 |
5 | 3210001411320214303 |
6 | 43524343355224031 |
7 | 2523051306613453 |
oct | 276756032441023 |
9 | 51415705527081 |
10 | 13123011101203 |
11 | 41aa48a717803 |
12 | 157b3b1a48017 |
13 | 742657942b73 |
14 | 33522b223d63 |
15 | 17b55db7581d |
hex | bef706a4213 |
13123011101203 has 2 divisors, whose sum is σ = 13123011101204. Its totient is φ = 13123011101202.
The previous prime is 13123011101201. The next prime is 13123011101237. The reversal of 13123011101203 is 30210111032131.
13123011101203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13123011101203 - 21 = 13123011101201 is a prime.
Together with 13123011101201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13123011101201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561505550601 + 6561505550602.
It is an arithmetic number, because the mean of its divisors is an integer number (6561505550602).
Almost surely, 213123011101203 is an apocalyptic number.
13123011101203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123011101203 is an equidigital number, since it uses as much as digits as its factorization.
13123011101203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13123011101203 its reverse (30210111032131), we get a palindrome (43333122133334).
The spelling of 13123011101203 in words is "thirteen trillion, one hundred twenty-three billion, eleven million, one hundred one thousand, two hundred three".
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