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13123012321033 is a prime number
BaseRepresentation
bin1011111011110111000001…
…1111001101111100001001
31201110112210021212220101121
42332331300133031330021
53210001412123233113
643524343441315241
72523051323154016
oct276756037157411
951415707786347
1013123012321033
1141aa49038022a
12157b3b2335b21
13742657c7c164
1433522b46070d
1517b55dd16e8d
hexbef707cdf09

13123012321033 has 2 divisors, whose sum is σ = 13123012321034. Its totient is φ = 13123012321032.

The previous prime is 13123012320997. The next prime is 13123012321051. The reversal of 13123012321033 is 33012321032131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12705175482624 + 417836838409 = 3564432^2 + 646403^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123012321033 - 233 = 13114422386441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13123012320989 and 13123012321007.

It is not a weakly prime, because it can be changed into another prime (13123012321633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561506160516 + 6561506160517.

It is an arithmetic number, because the mean of its divisors is an integer number (6561506160517).

Almost surely, 213123012321033 is an apocalyptic number.

It is an amenable number.

13123012321033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13123012321033 is an equidigital number, since it uses as much as digits as its factorization.

13123012321033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 13123012321033 its reverse (33012321032131), we get a palindrome (46135333353164).

The spelling of 13123012321033 in words is "thirteen trillion, one hundred twenty-three billion, twelve million, three hundred twenty-one thousand, thirty-three".